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Comment on the nature of two S−O bonds formed in SO2 molecule. Are the two S−O bonds in this molecule equal?

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The electronic configuration of S is 1s2 2s2 2p6 3s2 3p4.
During the formation of SO2, one electron from 3p orbital goes to the 3d orbital and S
undergoes sp2 hybridization. Two of these orbitals form sigma bonds with two oxygen
atoms and the third contains a lone pair. p-orbital and d-orbital contain an unpaired
electron each. One of these electrons forms pπ- pπ bond with one oxygen atom and the
other forms pπ- dπ bond with the other molecule. This is the reason SO2 has a bent structure. Also, it is a resonance hybrid of structures I and II.

Both S−O bonds are equal in length (143 pm) and have a multiple bond character.

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