Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
37.2k views
in Physics by (130k points)

About 5% of the power of a 100 W light bulb is converted to visible radiation. What is the
average intensity of visible radiation (a) at a distance of 1 m from the bulb?
(b) at a distance of 10 m?
Assume that the radiation is emitted isotropically and neglect reflection.

1 Answer

0 votes
by (93.8k points)
edited by
 
Best answer

Power rating of bulb, P = 100 W 

It is given that about 5% of its power is converted into visible radiation. 

Power of visible radiation,

Hence, the power of visible radiation is 5W.
(a) Distance of a point from the bulb, d = 1 m 

Hence, intensity of radiation at that point is given as:

(b) Distance of a point from the bulb, d1 = 10 m
Hence, intensity of radiation at that point is given as:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...