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Let us find two natural numbers which differ by 3 and whose squares have the sum 117.

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Let us find two natural numbers which differ by 3 and whose squares have the sum 117.
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1 Answer

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Best answer

Let the numbers be x and x – 3

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Sry sir...I want to say that from where the -6x come from?? ...I have not understand...
by (47.4k points)
(a - b)^2 = a^2 + b^2​​​​​​​ - 2ab
So,
(x - 3)^2 = x^2 + 3^2 - 2 * x * 3 = x^2 + 9 - 6x

So, your doubt is clear....
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