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In an equilateral triangle ABC, D is a point on side BC such that BD=1/3 BC Prove that 9AD2 = 7AB2

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Given: An equilateral triangle ABC and D be a point on BC such that BD=1/3 BC.

To Prove: 9AD2 = 7AB2
Construction: Draw AE ⊥ BC.
Proof: ∆ABC is an equilateral triangle and AEBC= BE = EC
Thus, we have

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