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+3 votes
11.3k views
in Mathematics by (50.9k points)
edited by

If \(\int\limits_0^{100\pi}\cfrac{sin^2x}{e^{(\frac{x}{\pi}-[\frac{x}{\pi}])}}dx\) \(=\frac{\alpha\pi^3}{1+4\pi^2},\) α ∈ R where [x] is the greatest integer less than or equal to x, then the value of α is :

∫ sin2x/e(x/π-[x/π])dx x ∈ [0, 100π] = απ3/1+4π2

(1) 200 (1 – e–1 )

(2) 100 (1 – e)

(3) 50 (e – 1)

(4) 150 (e–1 –1)

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1 Answer

+2 votes
by (49.4k points)

Answer is: (1) 200 (1 – e-1)

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