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in Physics by (46.2k points)

किसी परमाणु के ऊर्जा स्तर A, B और C ऊर्जा के बढ़ते हुए मानों अर्थात् \(E_A < E_B<E_C\) के तदनुरूप हैं । मान लीजिए संक्रमण C से B, B से A तथा C से A के तदनुरूप विकिरणों के तरंगदैर्ध्य क्रमशः \(\lambda_1 , \lambda_2\) और \(\lambda_3\) हैं। तब \(\lambda_1 , \lambda_2\) और \(\lambda_3\) के बीच सही संबंध है :

(A) \(\lambda_1^2 + \lambda_2^2 = \lambda_3^2\)

(B) \(\frac 1 {\lambda_1 } + \frac 1{\lambda_2} = \frac 1{\lambda_3}\)

(C) \(\lambda_1 + \lambda_2 + \lambda_3 = 0\)

(D) \(\lambda_1 + \lambda_2 = \lambda_3 \)

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1 Answer

+1 vote
by (46.8k points)

सही विकल्प है (B) \(\frac 1 {\lambda_1} + \frac 1{\lambda_2} = \frac 1{\lambda_3}\)

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