Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
66 views
in Mathematics by (49.9k points)

\(x^2 - 2\sqrt x - \sqrt 3 = 0\) and \(P_n =\alpha^n + \beta ^n\). The value of \(P_{12 } - \sqrt 2P_{11} - \sqrt 3 P_{10} + P_{11} - \sqrt 2P_{10}\) is

(1) \(\sqrt 3 P_9\)

(2) \((2 + \sqrt 5) P_9\)

(3) \(\sqrt 5 P_9\)

(4) \((3 + \sqrt 5) P_9\)

Please log in or register to answer this question.

1 Answer

+1 vote
by (50.1k points)

Correct option is (1) \(\sqrt 3 P_9\)

x2 - 2x - 3 = 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...