Given: W = 50 kN = 50 × 103 N ; L = 100 mm ; x = 1.4 m ; σb = 100 MPa = 100 N/mm2
The axle with wheels is shown in figure.
A little consideration will show that the maximum bending moment acts on the wheels at C and D. Therefore maximum bending moment,
*M = W.L = 50 × 103 × 100 = 5 × 106 N-mm
Let d = Diameter of the axle.
We know that the maximum bending moment (M),
\(5 \times 10^6= \frac\pi {32} \times \sigma _b \times d^3 = \frac \pi{32} \times 100 \times d^3 = 9.82 \ d^3\)
∴ d3 = 5 × 106 / 9.82 = 0.51 × 106 or d = 79.8 say 80 mm