Correct option is : (3) \( \frac{1}{27}\left(\frac{m_{2}}{m_{1}}\right)^{3}\)
\(\frac{\pi \mathrm{r}_{1}^{2}}{\mathrm{~T}_{\mathrm{A}}}=\frac{\mathrm{L}}{2 \mathrm{m}_{1}}\) ..........(1)
\(\frac{\pi \mathrm{r}_{2}^{2}}{\mathrm{~T}_{\mathrm{B}}}=\frac{3 \mathrm{L}}{2 \mathrm{m}_{2}}\) ...........(2)
\(\Rightarrow \frac{\mathrm{T}_{\mathrm{A}}}{\mathrm{T}_{\mathrm{B}}}=3 \cdot \frac{\mathrm{m}_{1}}{\mathrm{~m}_{2}} \cdot\left(\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}\right)^{2}\)
\(\left(\frac{\mathrm{T}_{\mathrm{A}}}{\mathrm{T}_{\mathrm{B}}}\right)^{2}=\left(\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}\right)^{3} \Rightarrow\left(\frac{\mathrm{r}_{1}}{\mathrm{r}_{2}}\right)^{2}=\left(\frac{\mathrm{T}_{\mathrm{A}}}{\mathrm{T}_{\mathrm{B}}}\right)^{\frac{4}{3}}\)
\(\Rightarrow \frac{1}{27} \cdot\left(\frac{\mathrm{m}_{2}}{\mathrm{~m}_{1}}\right)^{3}=\left(\frac{\mathrm{T}_{\mathrm{A}}}{\mathrm{T}_{\mathrm{B}}}\right)\)