Correct option is : (2) 205 J
\(\mathrm{W}_{\mathrm{AB}}=\int \mathrm{PdV}\) (Assuming \(\mathrm{T}\) to be constant)
\(
=\int \frac{\mathrm{RTdV}}{\mathrm{V}^{3}}
\)
\(
\begin{aligned}
=\mathrm{RT} \int_{2}^{4} \mathrm{~V}^{-3} \mathrm{dV}
\end{aligned}
\)
\(
\begin{aligned}
=8 \times 300 \times\left(-\frac{1}{2}\left[\frac{1}{4^{2}}-\frac{1}{2^{2}}\right]\right)
\end{aligned}
\)
\(=225 \mathrm{~J}\)
\(\mathrm{W}_{\mathrm{BC}}=\mathrm{P} \int_{4}^{2} \mathrm{dV}=10(2-4)=-20 \mathrm{J}\)
\(\mathrm{W}_{\mathrm{CA}}=0\)
\(\therefore \mathrm{W}_{\text {cycle }}=205 \mathrm{~J}\)
