Question

A straight line L1 passes through the point (-1,3) and (11,12),Find the equation for L1 in form of AX+By+C=0

Answer 1

Since the equation we have to find in the form of Ax+By+C=0.

And it passes through the points (-1,3) and (11,12), we can write equation in form of 

y-y₁ = (y₂-y₁/ x₂-x₁) * (x - x₁)

x₁=-1,y₁=3,x₂=11,y₂=12 putting these value in the equation we get,

y-3=3/4*(x+1)

4y-12=3x+3

3x-4y+15=0.