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Find the largest number of four digits exactly divisible by 12, 15, 18 and 27

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Find the largest number of four digits exactly divisible by 12, 15, 18 and 27

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The largest number of four digits = 9999

LCM of 12, 15, 18, 27 is 540

Dividing 9999 by 540

We get 279 as the remainder

LCM = 2 × 3 × 3 × 2 × 5 × 3 = 540

Required number = 9999 – 279 = 9720

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