Let the equation of the circle with centre (h, k) and radius ′′ be
(x− h)2 + (y − k)2 = r2 (1)
The two diameters of the circle are
x − y = 9 (2)
x − 2y = 7 (3)
Since the centre of a circle always lie on the diameter, so
(2) ⇒ h− k = 9 (4)
(3) ⇒ h − 2k = 7 (7)
(4) − (5) ⇒ k = 2
(4) ⇒ h = 11
∴ centre = (11, 2)
Also,
\(\pi r^2 = 38.5\)
∴ (1) ⇒ \({{(x-11)}^{2}}+{(y-2)^{2}}=\frac{49}{4}\)
, is the required equation of the circle