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+2 votes
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If f :R → R is a function defined by f(x) = 3x – 2

1. Show that f is one-one.

2. Find fof(x).

3. Find the inverse of f if exists.

1 Answer

+2 votes
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Best answer

1. f(x1) = f(x2)
⇒ 2x1 – 3 = 2x2 – 3 ⇒ x1 = x2
Therefore one-one.

2. fof(x) = f(f(x)) = f(3x – 2)
f (x) = 3(3x – 2) – 2 = 9x – 6 – 2 = 9x – 8.

3. Let g(x) = \(\frac{x+2}{3}\)

fog(x) = f(g(x))

= f\((\frac{x+2}{3})\) = 3\((\frac{x+2}{3})\) - 2 = x

Similarly we can show that
gof(x) = g(f(x)) = x

Therefore; f-1 = \((\frac{x+2}{3})\)

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