1. f(x1) = f(x2)
⇒ 2x1 – 3 = 2x2 – 3 ⇒ x1 = x2
Therefore one-one.
2. fof(x) = f(f(x)) = f(3x – 2)
f (x) = 3(3x – 2) – 2 = 9x – 6 – 2 = 9x – 8.
3. Let g(x) = \(\frac{x+2}{3}\)
fog(x) = f(g(x))
= f\((\frac{x+2}{3})\) = 3\((\frac{x+2}{3})\) - 2 = x
Similarly we can show that
gof(x) = g(f(x)) = x
Therefore; f-1 = \((\frac{x+2}{3})\)