Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.2k views
in Inverse Trigonometric Functions by (28.9k points)
closed by

(i) Choose the correct answer from the Bracket.

If cos-1x = y, then y is equal to

(a) π ≤ y ≤ π

(b) 0 ≤ y ≤ π

(c) −\(\frac{π}{2} ≤ y ≤ \frac{π}{2}\) 

(d) 0 ≤ y ≤ π

(ii) Find the value of cos-1 cos(\(\frac{7π}{3}\))

(iii) Solve for x if, tan-1(\(\frac{1+x}{1-x}\)) = 2 tan-1x

1 Answer

+1 vote
by (28.2k points)
selected by
 
Best answer

(i) Range of cos-1x is [0, π] ⇒ 0 ≤ y ≤ π

(ii) Here (\(\frac{7π}{3}\)) lie outside the interval [0, π]. TO make it in the interval proceed as follows.

(iii)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...