(i) Given,
x = a sec3θ
Differentiate w.r.to θ, we get;
\(\frac{dx}{dθ}\) = 3a sec2θ. secθ. tanθ = 3a sec3 θ. tan θ
Given,
y = a tan3θ .
Differentiating w.r.to θ, we get
\(\frac{dx}{dθ}\) = 3a tan2 θ. sec2θ.
(iii) We have,
\(\frac{dy}{dx}\) = sinθ
Differentiating w.r.to x, we get
(iv) We have,