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in Algebra by (36.3k points)
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The sum of three consecutive integers must not be more than 12. What are the integers?

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Let the three consecutive integers be x, (x + 1) and (x + 2). Since, sum of these integers must not be more than 12, i.e. x + (x + 1) + (x + 2) cannot exceed 12, therefore, we have

⟹ x + (x + 1) + (x + 2) ≤ 12

⟹ 3x + 3 ≤ 12

⟹ 3x + 3 − 3 ≤ 12 − 3

[Subtracting 3 from both sides]

⟹ 3x ≤ 9

⟹ x ≤ 3

[Dividing both sides by 3]

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