Let the three consecutive integers be x, (x + 1) and (x + 2). Since, sum of these integers must not be more than 12, i.e. x + (x + 1) + (x + 2) cannot exceed 12, therefore, we have
⟹ x + (x + 1) + (x + 2) ≤ 12
⟹ 3x + 3 ≤ 12
⟹ 3x + 3 − 3 ≤ 12 − 3
[Subtracting 3 from both sides]
⟹ 3x ≤ 9
⟹ x ≤ 3
[Dividing both sides by 3]