Question

Find the range of the following functions   f(x) = x²+ 2

Answer 1

Given, f(x) = x² + 2 

Let y = f (x)

y =  x²+ 2 

x² = y – 2 

x = \(\sqrt{y-2}\) 

Clearly, x will take real values, if 

Y – 2 ≥ 0 Y ≥ 2 

∴ Range of y = [2, ∞)