Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Physics by (34.6k points)

The velocity of a particle is v = v0 + gt + Ft2. Its position is x = 0 at t = 0 ; then its displacement after time (t = 1) is :

(1) v0 + g + F

(2) v0 + \(\frac g2\) + \(\frac F3\) 

(3) v0 + \(\frac g2\)+ F

(4) v0 + 2g + 3F

Please log in or register to answer this question.

1 Answer

+1 vote
by (35.0k points)

Correct option is (2) v0\(\frac g2+\frac F3\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...