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in Continuity and Differentiability by (27.0k points)
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If \(f(x) = \begin{cases} \frac{x^2-16}{x-4} & \quad \text{if } x ≠{4}\\ k, & \quad \text{if } x={ 4} \end{cases} \) is continuous at x = 4, find k.

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Formula : -

(i) A function f(x) is said to be continuous at a point x=a of its domain, if 
\(\lim\limits_{x \to a}f(x)\) = f(a)

\(f(x) = \begin{cases} \frac{x^2-16}{x-4} & \quad \text{if } x ≠{4}\\ k, & \quad \text{if } x={ 4} \end{cases} \)

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