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Check whether 6n can end with the digit 0 for any natural numbers n.

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If any number ends with the digit 0, it should be divisible by 10 or in other words its prime factorization must include primes 2 and 5 both as 10 = 2 ×5

Prime factorization of 6n = (2 ×3)n

In the above equation it is observed that 5 is not in the prime factorization of 6n

By Fundamental Theorem of Arithmetic Prime factorization of a number is unique.

So 5 is not a prime factor of 6n.

Hence, for any value of n, 6n will not be divisible by 5.

Therefore, 6n cannot end with the digit 0 for any natural number n.

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