We have,
ABCD is a rhombus
AC and BD are the diagonals with length 10cm and 24 cm respectively.
We know that rhombus of diagonal bisects each other at 90º
∴ AO = OC = 5cm and BO = OD = 12cm
In ΔAOB
AB2 = AO2 + BO2
AB2 = 52 + 122
AB2 = 25 + 144
AB2 = 169
AB = \(\sqrt{169}\)
AB = 13 cm