Time = distance/speed
Now, express train takes 1 hour less than a passenger train to travel 132 km between Mysore and Bangalore. The average speed of the express trains is 11 km / hr more than that of the passenger train.
Let the average speed of passenger train be ‘a’.
\(\frac{132}{a}-\frac{132}{a+11}=1\)
⇒ 132 ×(a + 11 –a) = a2 + 11a
⇒ a2 + 11a – 1452 = 0
⇒ a2 + 44a – 33a – 1452 = 0
⇒ a(a + 44) – 33(a + 44) = 0
⇒ (a + 44)(a – 33) = 0
⇒ a = 33 km/hr
Speed of express train = 44 km/hr