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Determine two positive numbers whose sum is 15 and the sum of whose squares is minimum.

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Let the two positive numbers be a and b.

Given : 

a + b = 15 … (1)

Also, 

a2 + b2 is minima 

Assume, 

S = a2 + b2 (from equation 1) 

⇒ S = a2 + (15 – a)

⇒ S = a2 + 225 + a2 – 30a 

= 2a2 – 30a + 225

⇒ \(\frac{ds}{da}\) = 4a - 30

⇒ \(\frac{d^2s}{da^2}\) = 4

Since,

\(\frac{d^2s}{da^2}\) > 0

⇒ \(\frac{ds}{da}\)  = 0 will give minimum value of S.

4a – 30 = 0 

⇒ a = 7.5 

Hence, two numbers will be 7.5 and 7.5.

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