Draw a circle with centre O, draw a tangent PR touching circle at P.
Draw QP perpendicular to RP at a point P, QP lies in the circle.
Now,∠OPR = 90º
Also, ∠QPR = 90º
Therefore,∠OPR = ∠QPRThis is possible only when O lies on QP.
Hence, it is proved that the perpendicular at the point of contact to the tangent to a circle passes through the centre