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in Arithmetic Progression by (31.3k points)
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Find the sum of all integers between 100 and 550, which are multiples of 9.

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Best answer

a = 108 

L = 549 

D = 9 

549 = 108 + (n - 1)9 

549 = 99 + 9n 

9n = 450 

n = 50

\(S_n = \frac{50}{2} [216 + 49(9)]\)

= 16425

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