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in Surface Areas And Volumes by (30.2k points)
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Water in a canal 1.5 m wide and 6 m deep is flowing with a speed of 10 km/hr. How much area will it irrigate in 30 minutes if 8 cm of standing water is desired?

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Speed of flowing water = 10 km/hr 

In 30 minutes length of flowing water =10 × \(\frac{30}{60}\) km 

= 5 km = 5000 m 

Volume of flowing water in 30 minutes = 5000 × width × depth

 Width of canal = 1.5 m 

Depth of canal = 6 m 

Volume of canal = 5000 × 1.5 × 6 m

= 45000 m3 

Irrigated area in 30 minutes if 8 cm of flowing water is required 

\(\frac{45000}{0.08}\)

= 562500 m2

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