Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
455 views
in Trigonometry by (30.4k points)
closed by

What is the value of 6tan2θ - \(\frac{6}{cos^2θ}\) ?

1 Answer

+1 vote
by (30.5k points)
selected by
 
Best answer

To find: 6tan2θ - \(\frac{6}{cos^2θ}\) 

∵ secθ = \(\frac{1}{cosθ}\) 

⇒ sec2θ = \(\frac{1}{cos^2θ}\)

⇒6tan2θ - \(\frac{6}{cos^2θ}\) = 6tan2θ -6sec2θ = 6(tan2θ - sec2θ)

Now, as 1 + tan2θ = sec2θ 

⇒ tan2θ – sec2θ = – 1

⇒ 6tan2θ - \(\frac{6}{cos^2θ}\) = 6(tan2θ - sec2θ) = 6(-1) = - 6

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...