Given:
let the height of the cone be H and its base radius be R
This cone is divided into two parts through the mid-point of the height of the cone such that
ED||BC
Therefore
triangle AED is similar to triangle ABC
By the condition of similarity,
\(\frac{OE}{PC}\) = \(\frac{AO}{AP}\) = \(\frac{AO}{2AO}\)
⇒ \(\frac{OE}{R}\) = \(\frac{1}{2}\) ⇒ OE = \(\frac{R}{2}\)
Volume of a cone = \(\frac{1}{3}\) πr2h
Volume of the frustum = Volume of the cone ABC – Volume of the cone AED