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Points p, Q, R and S divide the segment joining the points A (1, 2) and B (6, 7) in 5 equal parts. Find the coordinates of the points P, Q and R.

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Here given points are A (1, 2) and B (6, 7) which is divided into 5 equal parts by points P, Q, R and S 

∴ AP = PQ= QR = RS = SB

The point P divides the line segment AB in the ratio 1:4. 

By section formula,

x = \(\frac{mx_2+nx_1}{m+n}\), y = \(\frac{my_2+ny_1}{m+n}\)

For point P,

x = \(\frac{1\times6+4\times1}{1+4}\) , y = \(\frac{1\times7+4\times1}{1+4}\)

x = 2 and y = 3 

∴ Coordinate of P is (2 ,3 ) 

The point Q divides the line segment AB in the ratio of 2:3. 

For point Q,

 x = \(\frac{2\times6+3\times1}{2+3}\) , y = \(\frac{2\times7+3\times1}{2+3}\)

x = 3 and y = 4 

∴ Coordinate of Q is (3 ,4 ) 

The point R divides the line segment AB in the ratio of 3:2. 

For point R,

 x = \(\frac{3\times6+2\times1}{3+2}\) , y = \(\frac{3\times7+2\times1}{3+2}\)

x = 4 and y = 5 

∴ Coordinate of R is (4 , 5 )

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