(i) Total number of possible outcomes, n(S) = 20
Number of favorable outcomes,
n(E) = 4
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{4}{20}\) = \(\frac{1}{5}\)
(ii) Total number of possible outcomes, n(S) = 19
Number of favorable outcomes,
n(E) = 15
∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{15}{19}\)