Question

Solve the following quadratic equations by factorization method: x² + (1 – 2i)x – 2i = 0

Answer 1

x² + (1 – 2i)x – 2i = 0 

Given x² + (1 – 2i)x – 2i = 0 

⇒ x² + x – 2ix – 2i = 0 

⇒ x(x + 1) – 2i(x + 1) = 0 

⇒ (x + 1)(x – 2i) = 0 

⇒ x + 1 = 0 or x – 2i = 0 

∴ x = –1 or 2i 

Thus, the roots of the given equation are –1 and 2i.