Subtracting both the equations we get,
x2 – 11x + a - x2 +14x + 2a = 0
3x – a = 0
x = \(\frac{a}{3}\)
Substituting it in first equation we get,
\(\Big(\frac{a}{3}\Big)^2\) - 11 \(\frac{a}{3}\) + a = 0
\(\frac{a^2}{9}\) - \(\frac{8a}{3}\) = 0
a2 - 24a = 0
a = 24
