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in Polygons by (30.3k points)
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What is the number of diagonals in a 

(i) heptagon 

(ii) octagon 

(iii) polygon of 12 sides

1 Answer

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Best answer

(i) Number of diagonals in Heptagon is

\(=n\,\times\frac{n\,-\,3}{2}\) [n represents number of sides]

\(=7\times\frac{7\,-\,3}{2}\)

\(=7\times\frac{4}{2}\)

= 14 

So, Number of diagonals in heptagon is 14.

(ii) Number of diagonals in Octagon is

\(=n\,\times\frac{n\,-\,3}{2}\) [n represents number of sides]

\(=8\times\frac{8\,-\,3}{2}\)

\(=8\times\frac{5}{2}\)

= 20 

So, Number of diagonals in octagon is 20.

(iii) Number of diagonals in polygon of 12 sides is

\(=n\,\times\frac{n\,-\,3}{2}\) [n represents number of sides]

\(=12\times\frac{12\,-\,3}{2}\)

\(=12\times\frac{9}{2}\)

= 54 

So, Number of diagonals in polygon of 12 sides is 54.

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