Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
213 views
in Polynomials by (88.7k points)
closed by
Find the product `(2a-3b-2c)(4a^(2)+9b^(2)+4c^(2)+6ab-6bc+4ca)`.

1 Answer

0 votes
by (97.2k points)
selected by
 
Best answer
`[2a+(-3b)+(-2c)][(2a)^(2)+(-3b)^(2)+(-2c)^(2)-2axx(-3b)-(-3b)(-2c)-(2a)(-2c)]`
`(x+y+z)(x^(2)+y^(2)+z^(2)-xy-yz-zx) " " ("where" x=2a, y=-3b " and" z=-2c)`
`=x^(3)+y^(3)+z^(3)+3xyz=(2a)^(3)+(-3b)^(3)+(-2c)^(3)-3xx2axx(-3b)xx(-2c)`
`=8a^(3)-27b^(3)-8c^(3)-36abc`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...