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A naturally occuring sample of lithium contains 7.42% of `""^(6)Li` and 92.58% `""^(7)Li`. The relative atomic mass of `""^(6)Li` is 6.015 and that of `""^(7)Li` is 7.016. Calculate the atomic mass of a naturally occuring sample of lithium.

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Atomic mass `=((6.015xx7.42)(7.016xx92.58))/(100)=6.94`

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