Let an be the nth term of the AP.
∴ an = 5 - 6n
Putting n = 1, we get
First term, \(a=a_1=5-6\times1=-1\)
Putting n = 2, we get
\(a_2=5-6\times2=-7\)
Let d be the common difference of the AP.
\(\therefore d=a_2-a_1=-7-(-1)=-7+1=-6\)
Sum of first n term of the AP, Sn