Let the number of terms be 2n with first term a and common difference d
To find : number of terms and the series
The last term is given as a + (2n - 1) d
It is given that the last term exceeds the first by \(20\frac{1}{2}\),
Solving (i), (ii) and (iii) we get
d = 1.5
Substituting d in (i) we get n = 4
And substituting d and n in (ii) we get a = 1.5
So,
The number of terms is 2n = 8, and the sequence is given by a, a + d, a + 2d….
1.5, 3, 4.5, 6,7.5,9,10.5,12