Given,
An AP whose first term is 2
To find : 20th term of an AP
It is given that the sum of the first five terms is one-fourth of the next 5 terms
So,
5a + 10d = \(\frac{1}{4}\)(5a + 35d)
20a + 40d = 5a + 35d
15a + 5d = 0
Substituting a as 2 we get,
d = - 6
Hence,
20th term is a + 19d = - 112