Given, AB = AC
We know that the tangents from an external point are equal
∴ AD = AF, BD = BE and CF = CE ........(i)
Now, AB = AC
\(\Rightarrow\) AD + DB = AF + FC
\(\Rightarrow\) AF + DB = AF + FC .......[from (i)]
\(\Rightarrow\) DB = FC
\(\Rightarrow\) BE = CE .......[from (i)]
Hence proved.