Given: lines are as follows:
3x − 4y = 0 … (1)
12y + 5x = 0 … (2)
y − 15 = 0 … (3)
Assuming:
In triangle ABC, let equations (1), (2) and (3) represent the sides AB, BC and CA, respectively.
Concept Used:
Point of intersection of two lines.
Explanation:
Solving (1) and (2):
x = 0, y = 0
Thus, AB and BC intersect at B (0, 0).
Solving (1) and (3):
x = 20 , y = 15
Thus, AB and CA intersect at A (20, 15).
Solving (2) and (3): x = −36 , y = 15
Thus, BC and CA intersect at C (−36, 15).
Let us find the lengths of sides AB, BC and CA.
Hence, coordinate of incenter and centroid are \(\Big(-\frac{16}{3},10\Big)\) and (-1,8)