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Prove that the parallelogram circumscribing a circle, is a rhombus.

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Prove that the parallelogram circumscribing a circle, is a rhombus.

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Given, a parallelogram ABCD circumscribes a circle with center O 

AB = BC = CD = AD 

We know that the tangents drawn from an external point to circle are equal

Hence, ABCD is a rhombus.

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