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The length of the hypotenuse of a right-angled triangle exceeds the length of the base by 2 cm and exceeds twice the length of the altitude by 1 cm. Find the length of each side of the triangle.

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Let the base and altitude of the right-angled triangle be x and y cm, respectively 

Therefore, the hypotenuse will be (x + 2) cm.

∴ (x + 2)2 = y2 + x2........(i)

Again, the hypotenuse exceeds twice the length of the altitude by 1 cm.

∴ h = (2y + 1)

⇒ x + 2 = 2y + 1

⇒ x = 2y - 1

Putting the value of x in (i), we get:

Thus, the base, altitude and hypotenuse of the triangle are 15 cm, 8 cm and 17 cm, respectively.

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