Given:
The equations of the lines are
3x + 4y − 7 = 0 … (1)
4x − 3y + 5 = 0 … (2)
To find:
Angles between two lines.
Explanation:
Let m1 and m2 be the slopes of these lines.
m1 = \(-\frac{3}{4}\) ,m2 = \(\frac{4}{3}\)
∵m1m2 = \(-\frac{3}{4}\times\frac{4}{3}=-1\)
Hence, the given lines are perpendicular. Therefore, the angle between them is 90°.
