Question

Find the equation of the straight lines passing through the origin and making an angle of 45° with the straight line √3x + y = 11

Answer 1

Given: 

Equation passes through (0, 0) and make an angle of 45° with the line 

To find: 

Equation of given line 

Explanation: 

We know that, the equations of two lines passing through a point x₁,y₁ and making an angleα with the given line y = mx + c are

y - y₁ = \(\frac {m±\,tan\ \,\alpha}{1±m\,tan\ \,\alpha}\) (x - x₁)

Here,x₁ = 0, y₁ = 0, α = 45° and m = √3

So, the equations of the required lines are

Hence, Equation of given line is y =(√3 - 2)x and y = (√3 + 2)x