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in Trigonometry by (29.9k points)
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An observer 1.5m tall is 28.5 away from a tower and the angle of elevation of the top of the tower from the eye of the observer is 45°. The height of the tower is

(a) 27m 

(b) 30m 

(c) 28.5m 

(d) None of these

1 Answer

+1 vote
by (30.3k points)
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Best answer

Let AB be the observer and CD be the tower.

Draw \(BE \perp CD,\) let CD = h meters. Then,

Hence, the height of the tower is 30 m.

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