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If the lines x + ay + a = 0, bx + y + b = 0 and cx + cy + 1 = 0 are concurrent then write the value of 2abc – ab – bc – ca.

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Given: 

Lines x + ay + a = 0, bx + y + b = 0 and cx + cy + 1 = 0 

To find: 

The value of 2abc – ab – bc – ca. 

Explanation: 

The given lines are

x + ay + a = 0 … (1) 

bx + y + b = 0 … (2) 

cx + cy + 1 = 0 … (3) 

It is given that the lines (1), (2) and (3) are concurrent.

⇒ (1 – bc) – a(b – bc) + a(bc – c) = 0 

⇒ 1 – bc – ab + abc + abc – ac = 0 

⇒ 2abc – ab – bc – ca = -1 

Hence, the value of 2abc − ab − bc − ca is − 1

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