Given:
Lines y = mx + 1 and 3x + 4y = 9
To find:
The integral values of m
Explanation:
The given lines can be written as
mx – y + 1 = 0 … (1)
3x + 4y – 9 = 0 … (2)
Solving (1) and (2) by cross multiplication, we get:
For x to be integer we have, 4m + 3 = 1, -1, 5 and -5
⇒ m = \(-\frac{1}{2}\) ,-1,\(\frac{1}{2}\) and -2
Hence, the integral values of m are -1 and -2