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A hemispherical bowl made of brass has inner diameter 10.5 cm. Find the cost of tinplating it on the inside at the rate of Rs 16 per 100 cm2. [ Assume π = 22/7 ]

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Inner radius (r) of hemispherical bowl = (10.5/2) cm = 5.25 cm

Surface area of hemispherical bowl = 2πr2

Therefore, the cost of tin-plating the inner side of the hemispherical bowl is Rs 27.72.

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