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A trolley, while going down an inclined plane, has an acceleration of `2 cm//s^(2)` starting from rest. What will be its velocity `3 s` after the start ?

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Here, `" "` Initial velocity, `u=0`
Final velocity, `v=?" "` (To be calculated)
Acceleration, `a=2" cm "s^(-2)`
And, `" "` Time, `t= 3 s`
Now, `" "v= u+at`
So, `" " v= 0+2xx3`
or `" " v= 6" cm "s^(-1)`
Thus, the velocity of trolley after 3 s will be 6 centimetres per second.

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